Python 十个加快编程效率的技巧

1.交换两个数字

1. x, y =10,20

2. print(x, y)

3. x, y = y, x

4. print(x, y)

输出

1. 10 20

2. 20 10

**

2.反转字符串**

1. a ="GeeksForGeeks"

2. print("Reverse is", a[::-1])

输出

1. Reverse is skeeGroFskeeG

**

3.连接列表中的元素**

1. a =["Geeks","For","Geeks"]

2. print(" ".join(a))

输出

1. GeeksForGeeks

**

4.多比较符**

1. n =10

2. result = 1 < n < 20

3. print(result)

4. result = 1 > n <= 9

5. print(result)

输出

1. True

2. False

**

5.输出模块的位置**

1. import os;

2. import socket;

4. print(os)

5. print(socket)

输出

1. 'os'from'/usr/lib/python3.5/os.py'><>

2. 'socket'from'/usr/lib/python3.5/socket.py'><>

**

6.使****用枚举**

1. classMyName:

2. Geeks,For,Geeks= range(3)

4. print(MyName.Geeks)

5. print(MyName.For)

6. print(MyName.Geeks)

输出

1. 2

2. 1

3. 2

**

7.函数返回多个值**

1. def x():

2. return 1,2,3,4

3. a, b, c, d = x()

4. print(a, b, c, d)

输出

1. 1 2 3 4

**

8.找到数组中出现频率最高的数**

1. test =[1,2,3,4,2,2,3,1,4,4,4]

2. print(max(set(test), key = test.count))

输出

1. 4

**
9.检查对象占用内存大小**

1. import sys

2. x =1

3. print(sys.getsizeof(x))

输出

1. 28

**

10.检查两个字符串是否字谜（字母和出现次数一致）**

1. from collections importCounter

2. def is_anagram(str1, str2):

3. returnCounter(str1)==Counter(str2)

4. print(is_anagram('geek','eegk'))

6. print(is_anagram('geek','peek'))

输出

1. True

2. False