脉冲调制，每20ms脉冲有不同的位置

Hi Antoine - 命令 - ：SOURce：PULM：INTernal：DELay [1] | [2] | UP | DOWN设置相对于脉冲同步信号的延迟。
如果使用，则根据这些参数设置延迟。
例如：SOURce：PULM：INTernal：DELay1 0.01ms设置10usec的延迟。
| UP | DOWN参数与第二个命令一起使用 - ：SOURce：PULM：INTernal：DELay：STEP例如：SOURce：PULM：INTernal：DELay：步骤0.01ms将延迟步长设置为10usec。
现在使用：SOURce：PULM：INTernal：DELay1 UP每次递增延迟10usec。
我不太清楚你要做什么。
你打电话给18个信号时间吗？
你每20mS移回一次脉冲是什么意思？
脉冲是连续运行还是外部触发？
你是否在1.1mS内错开了一个脉冲？
问候 -



     以下为原文

  Hi Antoine -

The command –
:SOURce:PULM:INTernal:DELay[1]|[2] |UP|DOWN
Sets the delay relative to the pulse sync signal.
If  is used then the delay is set according to these parameters.
For example :SOURce:PULM:INTernal:DELay1 0.01ms sets the delay for 10usec.

The |UP|DOWN parameters are used in conjunction with the second command –
:SOURce:PULM:INTernal:DELay:STEP  
For example :SOURce:PULM:INTernal:DELay:STEP 0.01ms
Set the delay step to be 10usec. Now using 
:SOURce:PULM:INTernal:DELay1 UP
Increment the delay by 10usec each time.

It is not quite clear to me what you are trying to do.
Are you calling 18 periods of you signal one bit?
What do you mean by moving the pulses back every 20mS?
Are the pulses running continuous or are they externally triggered?
Are you staggering one pulse across the 1.1mS?

Regards -

首先感谢您的回答，实际上我有一些位，每个位由20个代码组成，每个代码由100个芯片组成。
因此，一位由20x1000个芯片组成。
一位持续20ms，每个代码C / A代码持续1ms。
所以我想要做的就是每个C / A码的1/10。
这就是为什么我设置0.1ms的脉冲宽度并且我希望在10ms内覆盖整个C / A码，因此我设置了1.1ms的脉冲周期，这样对于每个C / A码，脉冲向前移动0.1ms。
然后，对于第一个C / A，我覆盖了100个第一个芯片，在第二个C / A上我覆盖了从101到200等的芯片...... 10毫秒后，我覆盖了1000个芯片。
我想我成功了，但现在我想改变顺序。
我的意思是在第11毫秒，我不希望脉冲在第一个芯片开始，但在第50个开始，例如。
所以这意味着延迟-10.5毫秒。
你觉得这有可能吗？
我希望我足够清楚......谢谢你的帮助！
安托万



     以下为原文

  First of all thanks for your answer,

actually I have some bits, and each bit is composed of 20 codes C/A (all the sames) composed of 1000 chips. Thus, one bit is made up of 20x1000 chips. One bit lasts 20ms and each code C/A code lasts 1ms.

     So what I want to do, it is to pulse 1/10 th of each C/A code. That's why I set a pulse width of 0.1ms and I want to cover the whole C/A code during 10ms thus I set a pulse period of 1.1ms so that for each C/A code the pulse is moved forward of 0.1ms. 
Then for the first C/A I cover the 100 first chips, on the second C/A I cover the chips from 101 to 200 etc etc... After 10 ms I covered the 1000 chips.

I think I succeed to do that but now I want to change the sequence. I mean for the 11th ms I don't want the pulse to begin at the 1st chip but at the 50th for example. So It would mean to delay it of -10.5 ms. Do you think this is possible?

I hope I am clear enough... Thanks for your help!

Antoine

嗨Antoine - 谢谢你清理这个。
我现在对你的尝试有了更好的理解。
如果携带C / A码的信号是连续的那么似乎将脉冲宽度设置为0.1mS并且将周期设置为1.1mS将覆盖第一脉冲上的100个第一芯片然后覆盖第二脉冲上的下一个100，覆盖1000个芯片
你看到10毫秒后。
现在是第50个芯片......实现这一目标的一种方法是使用N5182A-320的脉冲序列选项：http：//www.home.agilent.com/en/pd-1871912-pn-N5182A-320/pulse-
火车发电机？cc = US＆amp; lc = eng您可以定义一个脉冲序列：ItemOn TimeOff Time Repeat 1.1ms1ms9 10.1ms10.5ms1 11.1ms1ms1注意：这会产生10个脉冲，允许您以100个芯片间隔脉冲1000个芯片然后有
延迟10.5ms，第11个脉冲从第50个芯片开始。
最后需要的是将脉冲与C / A信号同步。
问候 -



     以下为原文

  Hi Antoine -

Thanks for clearing this up. I now have a better understanding of what you are attempting. 

If the signal that carries the C/A code is continuous then it seems that setting the pulse width to .1mS and the period to 1.1mS would cover the 100 first chips on the first pulse then the next 100 on the second, covering 1000 chips after 10ms as you have seen. 

Now for the 50th chip…

One way to accomplish this is to use the pulse train option of the N5182A-320:
http://www.home.agilent.com/en/pd-1871912-pn-N5182A-320/pulse-train-generator?cc=US&lc=eng

You could define a pulse train:
Item     On Time     Off Time      Repeat
1     .1ms     1ms     9
10     .1ms     10.5ms     1
11     .1ms     1ms     1

Note: this produces the 10 pulses allowing you to pulse the 1000 chips in 100chip intervals then there is a 10.5ms delay and the 11th pulse begins at the 50th chip.

The last thing needed would be to synchronize the pulses with you C/A signal.

Regards -