LUT名称提取有什么合适的tcl命令吗

你好@ farzian
要提取已实现设计的LUT名称，请打开已实现的设计并在tcl控制台中运行以下命令：
show_objects -name find_1 [get_cells -hierarchical -filter {PRIMITIVE_TYPE = ~LUT。*。*}]
您将获得所有LUT的列表及其名称。
问候
罗希特
RegardsRohit -------------------------------------------------
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答案为“接受为解决方案”，如果提供的信息是有帮助的。给予您认为有用并回复导向的帖子。感谢K--
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在原帖中查看解决方案



以下为原文

Hi @farzian
 
To extract LUT names of the implemented design, Open the implemented design and run the below command in the tcl console:
show_objects -name find_1 [get_cells -hierarchical -filter { PRIMITIVE_TYPE =~ LUT.*.* } ]
 
You will get the list of all the LUTs along with their names.
 
Regards
Rohit
Regards
Rohit
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View solution in original post

你好@ farzian
要提取已实现设计的LUT名称，请打开已实现的设计并在tcl控制台中运行以下命令：
show_objects -name find_1 [get_cells -hierarchical -filter {PRIMITIVE_TYPE = ~LUT。*。*}]
您将获得所有LUT的列表及其名称。
问候
罗希特
RegardsRohit -------------------------------------------------
---------------------------------------------请注意 - 请注明
答案为“接受为解决方案”，如果提供的信息是有帮助的。给予您认为有用并回复导向的帖子。感谢K--
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以下为原文

Hi @farzian
 
To extract LUT names of the implemented design, Open the implemented design and run the below command in the tcl console:
show_objects -name find_1 [get_cells -hierarchical -filter { PRIMITIVE_TYPE =~ LUT.*.* } ]
 
You will get the list of all the LUTs along with their names.
 
Regards
Rohit
Regards
Rohit
----------------------------------------------------------------------------------------------
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嗨@ farzian，
您可以打开已实现的设计 - >查找（ctrl + f） - >选择PREMITIVE TYPE作为LUT，只有您可以找到相应的tcl命令。如果您点击确定，您将获得带有其单元格的LUT名称列表
单元引脚数。作为参考，我附上了快照。
谢谢和RegardsAsit -----------------------------------------------
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以下为原文

Hi @farzian,
 
You can Open Implemented design --> find (ctrl +f) --> select PREMITIVE TYPE as LUT and there only you can find the corresponding tcl command.
If yoo click on OK you will get the list of LUT names with their cells and cell pin count.

For your reference I have attached the snapshot.
 
Thanks and Regards
Asit
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我不明白如何解释表达式：= ~LUT。*。*有人可以解释一下这个意思吗？谢谢



以下为原文

I didn't understand how to interpret the expression :
=~ LUT.*.*

can someone explain the meaning?
thanks

你好@ pumaju1808
请为此查询打开一个新主题。
问候
罗希特
RegardsRohit -------------------------------------------------
---------------------------------------------请注意 - 请注明
答案为“接受为解决方案”，如果提供的信息是有帮助的。给予您认为有用并回复导向的帖子。感谢K--
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以下为原文

Hi @pumaju1808
 
Please open a new thread for this query.
 
Regards
Rohit
Regards
Rohit
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