STM8使用memcpy时会将内容复制到错误的地址

当目标存储器块位于零页面时，该地址通常从0x0到0xff。例如，如果目标存储器起始地址是0x0，则memory（）将内容从0x100复制到地址。 memory（）反汇编指令如：
LDW X，＆amp; sharpLength

循环：LD A，（scr + X）
LD（dst + X），A
DECW X.
JRNE循环
RET'scr'和'dst'的值是存储块起始地址1之前的地址。例如如果memcpy（）的'destination parameter'的起始地址是0x80，那么'dst'应该是0x7f，如果它的起始地址是0x0，'dst'将是0xff，那么内容将复制到内存从0x100。
我认为这应该是一个编译器问题。

#stm8-assembly #memcpy



以下为原文




When the destination memory block is locate in zero page which the address is often rang from 0x0 to 0xff. For instance, if a destination memory start address is 0x0, the memory() will copy the contents to address from 0x100. The memory() disassembly instructions like:
      LDW X, &sharpLength

loop: LD  A, (scr + X)
      LD (dst + X), A
      DECW X
      JRNE loop
      RETThe value of 'scr' and 'dst' is the address before 1 of start address of memory block. e.g. If the start address of 'destination parameter' of memcpy() is 0x80, then the 'dst' should be 0x7f, and if the start address of it is 0x0, the 'dst' will be 0xff, then the contents will copy to the memory from 0x100.
I thinks this should be a compiler issue.

#stm8-assembly #memcpy