[问答]

关于MSP430的代码问题，求各位高手指教

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问答对人有帮助，内容完整，我也想知道答案 0 想用MSP430G2553控制DAC0800输出扫频信号，256个采样点，扫频范围10～2000Hz，结果不输出波形，不知道哪里有问题，求各位前辈指教。代码如下： #include #include "stdint.h" static uint16_t f = 10; static uint16_t interval =0 ; const uint16_t temp[256]={ 0x7F,0x82,0x85,0x88,0x8B,0x8F,0x92,0x95,0x98,0x9B,0x9E,0xA1,0xA4,0xA7,0xAA,0xAD ,0xB0,0xB3,0xB6,0xB8,0xBB,0xBE,0xC1,0xC3,0xC6,0xC8,0xCB,0xCD,0xD0,0xD2,0xD5,0xD7 ,0xD9,0xDB,0xDD,0xE0,0xE2,0xE4,0xE5,0xE7,0xE9,0xEB,0xEC,0xEE,0xEF,0xF1,0xF2,0xF4 ,0xF5,0xF6,0xF7,0xF8,0xF9,0xFA,0xFB,0xFB,0xFC,0xFD,0xFD,0xFE,0xFE,0xFE,0xFE,0xFE ,0xFE,0xFE,0xFE,0xFE,0xFE,0xFE,0xFD,0xFD,0xFC,0xFB,0xFB,0xFA,0xF9,0xF8,0xF7,0xF6 ,0xF5,0xF4,0xF2,0xF1,0xEF,0xEE,0xEC,0xEB,0xE9,0xE7,0xE5,0xE4,0xE2,0xE0,0xDD,0xDB ,0xD9,0xD7,0xD5,0xD2,0xD0,0xCD,0xCB,0xC8,0xC6,0xC3,0xC1,0xBE,0xBB,0xB8,0xB6,0xB3 ,0xB0,0xAD,0xAA,0xA7,0xA4,0xA1,0x9E,0x9B,0x98,0x95,0x92,0x8F,0x8B,0x88,0x85,0x82 ,0x7F,0x7C,0x79,0x76,0x73,0x6F,0x6C,0x69,0x66,0x63,0x60,0x5D,0x5A,0x57,0x54,0x51 ,0x4E,0x4B,0x48,0x46,0x43,0x40,0x3D,0x3B,0x38,0x36,0x33,0x31,0x2E,0x2C,0x29,0x27 ,0x25,0x23,0x21,0x1E,0x1C,0x1A,0x19,0x17,0x15,0x13,0x12,0x10,0x0F,0x0D,0x0C,0x0A ,0x09,0x08,0x07,0x06,0x05,0x04,0x03,0x03,0x02,0x01,0x01,0x00,0x00,0x00,0x00,0x00 ,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x01,0x02,0x03,0x03,0x04,0x05,0x06,0x07,0x08 ,0x09,0x0A,0x0C,0x0D,0x0F,0x10,0x12,0x13,0x15,0x17,0x19,0x1A,0x1C,0x1E,0x21,0x23 ,0x25,0x27,0x29,0x2C,0x2E,0x31,0x33,0x36,0x38,0x3B,0x3D,0x40,0x43,0x46,0x48,0x4B ,0x4E,0x51,0x54,0x57,0x5A,0x5D,0x60,0x63,0x66,0x69,0x6C,0x6F,0x73,0x76,0x79,0x7C}; /* * main.c / int main(void) { WDTCTL = WDTPW \| WDTHOLD; // Stop watchdog timer /配置DCO为8MHz/ DCOCTL = CALDCO_8MHZ; BCSCTL1 = CALBC1_8MHZ; BCSCTL2 &= ~SELS; //配置SMCLK的时钟源为DCO BCSCTL2 &= ~(DIVS0 \| DIVS1); //SMCLK的分频系数置为1 uint16_t j = 0; uint16_t k = 0; interval = (int)8000000 / (f 256) - 1 ; P1DIR = 0xFF ; TA1CTL \|= TASSEL_2; //设置时钟源为SMCLK TA1CTL \|= MC_1; //工作模式为向上计数模式 TA1CCR0 = 49999; //每0.05s改变一次正弦波频率 TA1CTL \|= TAIE; //打开TAIFG中断 __bis_SR_register(GIE); //打开全局中断 while(1) { for(j=0 ; j < interval;j++); P1OUT=temp[k]; k++; if(k >= 256) k=0; } } #pragma vector=TIMER1_A1_VECTOR __interrupt void Timer1_A1(void) { switch(TA1IV) //判断是哪个标志源产生了中断 { case 0x02: break; case 0x04: break; case 0x0A: f=f+10; if(f>=2000) f=10; interval = 8000000 / (f * 256) - 1 ; break; default: break; } } 0
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答案对人有帮助，有参考价值 0 #pragma vector=TIMER1_A1_VECTOR __interrupt void Timer1_A1(void) { switch(TA1IV) //判断是哪个标志源产生了中断 { case 0x02: break; case 0x04: break; case 0x0A: f=f+10; if(f>=2000) f=10; interval = 8000000 / (f * 256) - 1 ; break; default: break; } } 你DEBUG一下看看有没有进入中断，进入的话数据时什么

2017-3-9 12:48:59 评论举报刘旭